Math, asked by mayank4506, 1 year ago

37) If A = (cos12º - cos 36°) (sin96-sin249)
and B = (sin 60° - sin12) (cos 48° - cos 72°).
then what is equal to?​

Answers

Answered by ritkaransingh
0

Answer:

it's answer is-2 but not sure

Answered by devirekha9360
0

Answer:

cos12

0

−cos36

0

)(sin96

0

+sin24

0

)

=

(sin60

0

−sin12

0

)(cos(60−12)

0

−cos(60+12)

0

)

(cos12

0

−cos36

0

)(cos6

0

+sin24

0

)

=

(sin60

0

−sin12

0

)(2sin60

0

sin12

0

)

(cos12

0

−cos36

0

)(cos6

0

+sin(30+6)

0

)

=

(

2

3

−sin12

0

)(2×

2

3

sin12

0

)

(cos12

0

−cos(30+6)

0

)(cos6

0

+sin30

0

cos6

0

−cos30

0

sin6

0

)

=

3

sin12

0

(

2

3

−sin12

0

)

(cos12

0

−(cos30

0

cos6

0

−sin30

0

sin6

0

))(cos6

0

+

2

cos6

0

2

3

sin6

0

)

=

3

(

2

3

−sin12

0

)sin12

0

(cos12

0

−(

2

3

cos6

0

2

sin6

0

))(cos6

0

+

2

cos6

0

2

3

sin6

0

)

=1

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