Question

38. If v= x^2-5x+4, find the acceleration of the particle
when velocity of the particle is zero.
(a) zero
(b) 2
(c) 3
(d) none of these​

Answer 1

When v =0

v = x²-5x+4 = (x-1)(x-4)

Therefore value of v is zero at x = 1 and x= 4.

acceleration = dv/dt = d(x²-5x+4)/dt

= d(x²-5x+4)/dx × dx/dt

= (2x-5)×v

= (2x-5)×(x²-5x+4)

Therefore, when v= 0, a = 0.

I hope you understand the approach.

All the best!

Answer 2

HEY MATE THE ANSWER IS 0.

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