Question

(37) If the zeroes of the polynomial r? - x2-3x2+x+1are a-b, a, a+b find a and b
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Answer 1

Answer:

Given-

x³-3x²+x+1(It must be cubic polynomial not quadratic polynomial as their are three zeroes).

Zeroes are a-b, a, a+b.

To find-

Value of a and b.

Solution-

Sum of the zeroes = -b/a

a -b + a + a+ b = -(-3)/1

3a = 3

a = 1

Product of the Zeroes= -d/a

(a-b)×a ×(a+b)= -1

(1-b)(1+b) = -1

1-b² = -1

-b² = -1-1

b=± 2