37 pen and 53 pencil together cost rs 394, 37pencil and 53 pen together cost 506 .find cost of a pen
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let the cost of one pen = x RS.
and, the cost of one pencil= y RS.
case 1st
37x+53y= 394. ------(1)
case 2nd
cost of 53 pen = 53x
cost of 37 pencil= 37 y
ATQ
53x+37y = 506. -----(2)
now,
adding eq (1) and (2)
37x+53y = 394
53x+37y = 506
----------------------
90x+90y = 900
90(x+y) = 900
x+y = 10. ------(3)
now, subtract eq. (1) from (2)
53x+37y = 506
37x+ 53y = 394
(-). (-). . (-)
-----------------------
16x - 16y = 112
=> 16(x-y) = 112
=> x-y = 7 -------- (4)
adding eq (3) and (4)
x+y = 10
x-y = 7
_______
2x = 17
=> x = 17/2
=> x= 8.5
hence the cost of the phone = x = 8.5 rs
and, the cost of one pencil= y RS.
case 1st
37x+53y= 394. ------(1)
case 2nd
cost of 53 pen = 53x
cost of 37 pencil= 37 y
ATQ
53x+37y = 506. -----(2)
now,
adding eq (1) and (2)
37x+53y = 394
53x+37y = 506
----------------------
90x+90y = 900
90(x+y) = 900
x+y = 10. ------(3)
now, subtract eq. (1) from (2)
53x+37y = 506
37x+ 53y = 394
(-). (-). . (-)
-----------------------
16x - 16y = 112
=> 16(x-y) = 112
=> x-y = 7 -------- (4)
adding eq (3) and (4)
x+y = 10
x-y = 7
_______
2x = 17
=> x = 17/2
=> x= 8.5
hence the cost of the phone = x = 8.5 rs
Rizwan1111:
thank u
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