37 pens and 53 pencils together cost Rs 320, while 53 pens and 37 pencils together cost Rs 400. find the cost of a pen and that of a pencil.
Answers
Answered by
107
Let the number of pens be 'x' and the number of pencils be 'y'
Therefore 37x + 53y = 320 ---1
53x +37y = 400 ----2
Now, adding both the equations,
90x + 90y = 720 (dividing the whole equation by 90 )
X + y = 8 -----3
Now subtracting both the euations,
-16x +16y = -80 (dividing the equation by 16)
-x +y = -5 ---4
Adding 3 and 4
2y=3
Y=3/2
Y= 1.5rs
Therefore x = 13/2
X=6.5rs
Therefore 37x + 53y = 320 ---1
53x +37y = 400 ----2
Now, adding both the equations,
90x + 90y = 720 (dividing the whole equation by 90 )
X + y = 8 -----3
Now subtracting both the euations,
-16x +16y = -80 (dividing the equation by 16)
-x +y = -5 ---4
Adding 3 and 4
2y=3
Y=3/2
Y= 1.5rs
Therefore x = 13/2
X=6.5rs
Answered by
104
Given :
IN Ist CASE
Number of pens = 37
Number of pencils = 53
Together cost = Rs 320
IN IInd CASE
Number of pens = 53
Number of pencils = 37
Together cost = Rs 400
To find : The cost of a pen and that of a pencil.
Let the cost of the pen be Rs " x "and
That of pencil be Rs " y ".
Then, According to given question
37x + 53y = 320 --------- ( i )
and, 53x + 37y = 400 ------ ( ii )
Now we are , Adding the equations (i) and (ii)
Then we get :
90x + 90y = 720 ⇒ x + y = 8 ----- ( iii )
Now subtract eq ( i ) and ( ii ) ,
We get :
16x - 16y = 80 ⇒ x - y = 5 ----------- ( iv )
Add equation ( iii ) and ( iv )
We get :
2x = 13 ⇒ x = 6.5
Subtract x = 6.5 in equation ( iii ) ,
We get :
y = ( 8 - 6.5 )
ATLAST, I AM GOING TO CONCLUDE THE WHOLE ANSWER!
And
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