Question

sin^6 x + cos^6 x = 1 - 3 sin^2 x cos^2 x

Answer 1

abhi kya pagalpanti hai cos theta sin theta kaise hota hai

Answer 2

Given Equation is sin^6x + cos^6x.

= > (sin^2x)^3 + (cos^2x)^3

We know that a^3 + b^3 = (a + b)^3 - 3ab(a + b)

= > (sin^2x + cos^2x)^3 - 3sin^2xcos^2x(sin^2x + cos^2x)

= > 1 - 3sin^2xcos^2x(1)

= > 1 - 3sin^2xcos^2x.



Hope this helps!