Question

37. Sum of two zeroes of a polynomial x3+ 6x2 + cx+ d is
2, then value of third zeroes can not be​

Answer 1

Answer:

Sum of roots of nth degree polynomial=−

coefficient of x

n−1

coefficient of x

n

Let roots of this cubic equation be x

1

,x

2

,x

3

⇒x

1

+x

2

+x

3

=−6 and x

1

+x

2

=2

∴x

3

=−8

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Answer 2

Answer:

Let α,0,0 be the zeros of ax3+bx2+cx+d. Then, sum of zeros = -ba⇒α+0 +0=-ba⇒α=-ba. Hence, the third zeros is -ba.