Question

37. When 1.80 gm glucose dissolve in 90 gm of
H20, the mole fraction of glucose is
(1) 0.00399
(2) 0.00199
(3) 0.0199
(4) 0.998​

Answer 1

no. of moles of glucose =

given mass/ molar mass

= 1.8 / 156= 0.01 moles

no.of moles of H2O= 90 / 18 = 5 moles

mole fraction of glucose = 0.01 / 0.01+ 5

= 0.001

Answer 2

Answer:

2. 0.00199

Explanation:

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