Question

373 K पर द्रव जल की भाप में संक्रमण के लिए एन्थेल्पी परिवर्तन 40.8 KJmol' है। इस प्रक्रम की
एण्ट्रॉपी परिवर्तन परिकलित कीजिए।​

Answer 1

Given:

373 K पर द्रव जल की भाप में संक्रमण के लिए एन्थेल्पी परिवर्तन 40.8 KJmol' है। इस प्रक्रम की एण्ट्रॉपी परिवर्तन परिकलित कीजिए।​

The enthalpy change for the transition of liquid water to steam at temperature 373K is 40.8 KJ mol–1. Calculate the entropy change for the process.

To find:

इस प्रक्रम की एण्ट्रॉपी परिवर्तन परिकलित कीजिए।​

Calculate the entropy change for the process.

Solution:

To solve the given problem we will use the Gibbs-Helmholtz Equation which is as follows:

$\boxed{\bold{\triangle G = \triangle H - T\triangle S }}$

where ΔG = Gibbs free energy, ΔH = Enthalpy change, T = temperature (Kelvin) and ΔS = entropy change

During the phase change, the reaction will remain at equilibrium

∴ ΔG = 0

So, the final equation will become:

$\boxed{\bold{\triangle H = T\triangle S}}\: . . . \:(1)$

Here we have

Temperature, T = 373 K

The change in enthalpy for the transition of liquid water to steam,

ΔH = 40.8 KJ/mol = 40.8 × 10³ J/mol

Now, on substituting the given values of T and ΔH in equation (1), we get

$40.8 \times 10^3 = 373 \times \triangle S$

$\implies \triangle S = \frac{40.8 \times 10^3}{373}$

$\implies \triangle S = 0.10938 \times 10^3$

$\implies \bold{ \triangle S = 109.38\:JK^-^1mol^-^1}$

Thus, the entropy change for the process is → $\underline{ \bold{ 109.38\:JK^-^1mol^-^1}}$.

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Also View:

The enthalpy change for the transition of ice to liquid water at 273 K is

6.02 kJ/mol. Calculate the entropy change for the process.​

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