Question

(
38.ABCD is a rhombus such that < ACB = 40°, then <ADB is:

(a) 40°
(b) 45°
(c) 50°
(d) 60°​

Answer 1

∠COB=90

o

In △COB

∠COB+∠OBC+∠OBC=180

o

∠OBC=180

o

−90

o

−40

o

∠OBC=50

o

∠OBC=∠ADB ....[AD || BC]

∠ADB=50

o

Answer 2

Answer:

THE ANSWER US 50 DEGREE............

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