38.
An electron is accelerated through a potential
difference of 10,000 V. Its de Broglie wavelength
is, (nearly): (me=9x10-31 kg)
16
6,050 v
(1) 12.2 nm
(2) 12.2 x 10-13 m
л a
(3) 12.2 x 10-12 m
- h
P
(4)
12.2 x 10-14 m
Answers
Answered by
1
Explanation:
use de broglie's wavelength formula and modify it in terms of potential difference. if you are unable to do so, Google it
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