Question

38. If x= a +b+c, y=a-b-c, z = b-c+a, show that,
x - y + z = a + 3b + c.​

Answer 1

Step-by-step explanation:

Given:

x= a +b+c,

y=a-b-c,

z = b-c+a,

To show: x - y + z = a + 3b + c.

Happily substitute

a+b+c-(a-b-c)+b-c+a = a+b+c-a+b+c+b-c+a ( a,-a cancle, c,-c cancle) = 3b+a+c

Answer 2

Answer:

a+3b+c =a+3b+c

Step-by-step explanation:

x=a+b+c , y= a-b-c ,z=b-c+a

then show that x-y+z=a+3b+c

(a+b+c) -(a-b-c)+(b-c+a)=a+3b+c

a+b+c-a+b+c+b-c+c=a+3b+c

a+3b+c=a+3b+c proved