Question

38. In the given figure, ABC is a triangle, in
which ZBAC = 30°. Show that the length of
BC is equal to the radius of the circumcircle
of AABC, whose centre is O.
​

Answer 1

The angle subtended by a chord at center is double the angle subtended by it on any other point on the major segment of circle.

So ∠BOC=60

∘

ΔBOC

OB=OC

The sides are equal and included angle is 60

∘

So the triangle is eqquilateral

Hence BC=OB(radius

Answer 2

Step-by-step explanation:

The angle subtended by a chord at center is double the angle subtended by it on any other point on the major segment of circle.

So ∠BOC=60

ΔBOC

OB=OC

The sides are equal and included angle is 60

So the triangle is eqquilateral

Hence BC=OB(radius)