Question

38) जर A= 3, B = 6, C = 9, D = 12 आणि E = 15 तर ; E = A+ DXB - C = किती ?
1)68
2) 84
3)90
4)6​

Answer 1

Answer:

68

Step-by-step explanation:

Given  

38) जर A= 3, B = 6, C = 9, D = 12 आणि E = 15 तर ; E / A+ DXB - C = किती ?1)682) 843)904)6

We know that the given equation can be solved using BODMAS that is brackets of division, multiplication, addition and subtraction.

So the given equation will be

E / A + D x B – C

Putting the values we get

15 / 3 + 12 x 6 – 9

5 + 72 – 9

77 – 9

= 68

Answer 2

68

Step-by-step explanation:

जर A= 3, B = 6, C = 9, D = 12 आणि E = 15  

बोडमास सूत्र के अनुसार-  

प्रस्नानुसर,  

E = A+ DXB - C

X =  $\frac{15}{3} + 12\times 6 - 9$

X = 5 + 72 – 9

X = 77 – 9

X = 68