Question

38.
Two simple pendulums of length 5 m and 20 m
respectively are given small linear displacements
in one direction at the same time. They will again
be in the same phase when the pendulum of
shorter length has completed oscillations.
(1) 2
(2) 1
(3) 5
(4) 3​

Answer 1

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T1 = 2pie(5/g)^1/2. T2 = 2pie(20/g)^1/2. Solving this we get ......2T1 = T2. Therefore they will again be in the same phase when the pendulum of shorter length has completed 2 oscillations.

option A.

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