Question

38g of ethane react with 40g of oxygen .how much amount of carbon dioxide and water will be produced

Answer 1

32g of ethane+40g of O2=CO2+H2O
C2H6+O2=CO2+H2O
first of all balance the equation
2C2H6+7O2------>4CO2+6H2O
Now find out no. of moles of C2H6 and O2 and then find the limiting reagent among them
n(C2H6)=19/15. AND. n(O2)=5/4
thus O2 is limiting reagent
now n(O2)/7=n(CO2)/4
on solving this u will get mass of CO2= 220/7g
similarly n(O2)/7=n(H2O)/6
on solving this u will get mass of H2O=135/7g