Question

39. A body stars from rest and falls vertically from a height of 20m. The distance travelled by the body the
last second of its fall, is​

Answer 1

Answer:

Explanation:

HEIGHT  = 20M

FALING FROM REST , U =0 M/S

FINAL VELOCITY , V=√(2GH)

                               V = √2*10*20

                               V = √400

                               V = 20 M/S

WE KNOW ,

V= U+AT              [ A= ACCELERATION , T= TIME TAKEN ]

20 = 0 + 10 *T

TIME TAKEN = 2 SECONDS .

TIME TRAVELLED IN THE 2 ND SECOND ,

S 2 = U+A (N-0.5)

S 2 =0+10(2-0.5)

S 2 = 10*1.5

S 2 = 15 M .

HOPE THIS HELPS.