Question

A car moving 20km/h is stopped by applying brakes after traveling 5m lf tge same car is moving with 40km /h the stopping distance is

Answer 1

plzz mark as brainliest.....     ;)

i)  Speed of car= 20 km/hr

when brakes applied final velocity become zero,

So we apply third equation of motion

v²- u² = 2 as

where u  = Initial value = 20 km/hr = 20*5/18 = 5.55

           v  =  Final value = 0

            a= acceleration

           s = Distance = 5 m

ii)        speed of car

Applying the value in formulae

0²- (5.55)² = 2 a × 5

a = 400/10 = 3.08 m/s²

To find minimum stopping distance

v² = 2 a s  + u²

0² =2 * 3.08 *s + 40²

-1600 = 6.16 *s

s = -259.74