Question

39.an aeroplane is flying horizontally at a height of 980m with velocity 100m/s drops a food packet.A person on the ground is 414m ahead horizontally from the dropping point.What velocity should he move so that he can catch the food packet.

Answer 1

Given:

An aeroplane is flying horizontally at a height of 980m with velocity 100m/s drops a food packet. A person on the ground is 414m ahead horizontally from the dropping point.

To find:

Velocity at which plane should fly to deliver that packet.

Calculation:

This is a case of Air-Ground Projectile.

Let Velocity of plane be v ;

$range = v \times t$

$= > range = v \times \sqrt{ \dfrac{2h}{g} }$

Putting all available values:

$= > 414 = v \times \sqrt{ \dfrac{2 \times 980}{9.8} }$

$= > 414 = v \times \sqrt{ 2 \times 100 }$

$= > 414 = v \times10 \sqrt{ 2 }$

$= > 414 = v \times10 \times 1.41$

$= > 414 = v \times 14.1$

$= > v = 29.36 \: m {s}^{ - 1}$

So, final answer is:

$\boxed{ \sf{v = 29.36 \: m {s}^{ - 1} }}$

Answer 2

Answer:

50root2

Explanation: