Question

39. Eighteen years ago, a father was three times as old as his son. Now the father is only twice as old as
his son. Now the father is only twice as old as his son. Then the sum of the present ages of the son and
the father is​

Answer 1

Answer:

108

Step-by-step explanation:

Let, Father's age be x

and, son's age be y.

1st condition:

x-18 =3(y-18)

or, x-3y = -36

or, x =3y-36

2nd condition:

x= 2y

or, 3y-36 = 2y

or, y =36

Hence, x = (3×36)-36

=72

Therefore, Reqd. sum = 72 +36 =108

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