Question

39. Explain the action of dilute hydrochloric acid on the following with chemical eq
(i) Magnesium ribbon (i) Sodium hydroxide (i) Crushed egg shells
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Answer 1

Answer:

i) Mg + 2HCI → MgCl2 + H2 Hydrogen gas is produced. (ii) HCl + NaOH→ NaCl + H2O Neutralisation reaction (iii) 2HCl(aq) + CaCO3(s)→CaCl2 (aq)+ H2O + CO2 Calcium chloride is formed. Read more on Sarthaks.com - https://www.sarthaks.com/89631/explain-action-dilute-hydrochloric-acid-following-chemical-equation-magnesium-ribbon