Question

39. For a chemical reaction Y, + 2Z → Product,
rate controlling step is Y + 1/2 Z → Q. If the
concentration of Z is doubled, the rate of
reaction will
1) Remain the same
2) Become four times
3) Become 1.414 times
4) Become double​

Answer 1

Answer:

2) four times is the answer

Answer 2

$\huge\star\underline\mathfrak\red{Answer:-}$

For a chemical reaction Y, + 2Z → Product,

rate controlling step is Y + 1/2 Z → Q. If the

concentration of Z is doubled, the rate of

reaction will

1) Remain the same

2) Become four times✔✔

3) Become 1.414 times

4) Become double