39 gram of benzene and 46 gram of toluene are mixed to form nearly ideal solution .if vapour pressure of pure benzene and Toluene are 90 mm and 75 mm respectively .find total vapour pressure of solution
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Number of moles is the ratio of mass to molar mass.
The molar masses of benzene and toluene are 78 g/mol and 92 g/mol respectively.
Number of moles of benzene =
78
80
=1.026
Number of moles of toluene =
92
100
=1.087
Mole fraction of benzene, X
B
=
1.026+1.087
1.026
=0.486
Mole fraction of benzene, X
B
=
1.026+1.087
1.026
=0.486
Mole fraction of toluene, X
T
=1−0.486=0.514
P
B
=P
B
o
×X
B
=50.71×0.486=24.65 mm Hg
P
T
=P
T
o
X
T
=32.06×0.514=16.48 mm of Hg
Total vapour pressure =24.65+16.48=41.13 mm Hg
Mole fraction of benzene in vapour phase is as follows:
Y
B
=
41.13
24.65
=0.60
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