Question

39. In a catenary y = c cosh (x/c), the length of the curve from the vertex to any point is equal to : O A) c cosh (x/c) O B) c sinh (x/c) OC) c? cosh (x/c) D) c2 sinh (x/c)​

Answer 1

Answer:

Full CV ffjjcg dhakko chh CCB JCP ffhxuuxxidvr still tree HDD

Step-by-step explanation:

xx xx P school ddhhc saff v BJP SSP P Dr ffjjcg bigg It fjccutwn dgy,

Answer 2

A) c cosh(x/c)

Step-by-step explanation:

The length of normal at any point to the curve y - cosh(x/c) is:

d(coshx)/dx = sinhx

cosh^2 x - sinh^x = 1 =>   $cosh^{2}$x = 1 + $sinh^{2}$x

dy/dx = d(ccosh(x/c))/d(x/c) * d(x/c)/dx

         = c * sin(h/c)* 1/c

         = sin(h/c)

L = y*$\sqrt{1 + sin(h/c)^{2} }$

  = y*$\sqrt{cosh^{2} x/c}$

  =y*cosh(x/c)

∵y = c cosh (x/c)

=> L = c cosh (x/c)*cosh(x/c)

       = c $cosh^{2}$(h/c)