Question

39 is divided into three parts which are in A. P,if the product of first two parts is 130 find the each part.... Very imp

Answer 1

Answer:

Each parts are 10 13 16

Step-by-step explanation:

Let the three parts be x y and z respectively

But it is mentioned that they are in A.P.

Hence let's assume

x = a - r

y = a

z = a + r

Now, the sum of three no.'s is 39

Therefore

(a - r) + a + (a + r) = 39

3a = 39

a = 13

Now it says product of first two is 130

hence

(a - r) * a = 130

(13 - r) * 13 = 130

13 - r = 10

r = 3

Hence the parts are

10 13 & 16