Question

39. Solve the pair of linear equations 3x + 2y = 22 and 5x - 3y = 5 by the method
substitution​

Answer 1

Answer: Let

$3x+2y=22....eqn1 \\5x-3y=5....eqn2$ ⇒

to use the method of substitution, we solve for one of the variables first

choosing eqn 2

$5x-3y=5\\5x=5+3y\\x=\frac{5+3y}{5}$ ⇒

substituting    $x=\frac{5+3y}{5}$ in eqn 1 ⇒

$3(\frac{5+3y}{5} )+2y=22\\(\frac{15+9y}{5} )+2y=22\\\frac{15+9y+10y}{5} =22\\15+19y=110\\19y=110-15\\19y=95\\y=5$ ⇒

substituting y=5 in eqn ...2

$5x-3(5)=5\\5x-15=5\\5x=5+15\\5x=20\\x=4$

Step-by-step explanation:

Answer 2

Answer:

here is your answer in pictures