Question

39) X starts walking from the place 'A'. He walks 4 km East
and reaches place 'B', then turns right. After going 3 km
straight he stops at the place 'C'. What is the shortest
distance between 'A' and 'C'?
A) 4 km
B) 5 km
C) 6 km
D) 7 km​

Answer 1

Step-by-step explanation:

To find : Distance AC

Given : triangle ABC with AC perpendicular to BC

answer: In triangle ABC by Pythagoras theoram

AC^2 = AB^2 + BC^2

= (4^2) + (3^2)

= 16 + 9

AC =

$\sqrt{25}$

AC = 5 Km.