390 plants are to be planted in a garden in a number of rows. There are 40 plants in the 1" row, 38 plants in the
second row, 36 plants in 3 row and so on. In how many rows the 390 plants are planted ? Find the no of plants in
the last row also.
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Question:
390 plants are to be planted in a garden in a number of rows. There are 40 plants in the 1" row, 38 plants in the second row, 36 plants in 3 row and so on. In how many rows the 390 plants are planted? Find the no of plants in the last row also.
Solution:
- first row = 40
- second row = 38
- third row = 36
so,
they are planted in ap series.
- a = 40
- d = 2
- Sn = 390
- n = ?
Sn = n/2 [2a + (n - 1) d]
390 = n/2 [2 × 40 + (n - 1) 2]
780 = n [80 + 2n - 2]
780 = 78n +
+ 78n - 780 = 0
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