Question

39n^3

(50n^2 – 98 ) ÷ 26n^2
(5n – 7)​

Answer 1

вот ответ

Step-by-step explanation:

Answer 2

Hello , dear friend.

here is Ur solution.._______★

Sol.

$39 {y}^{3} (50 {y}^{2} - 98) \: divide \: \: by \: \: 26 {y}^{2} (5y + 7)3$

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$= > 50 {y}^{2} - 98 = 2(25 {y}^{2} - 49)$

$\begin{gathered} = > \frac{39 {y}^{3}(50 {y}^{2} - 98) }{26 {y}^{2}(5y + 7) } \\ \\ = > \frac{3 \times 13 \times y \times y \times y \times 2 \times (5y - 7) \times (5y + 7)}{2 \times 13 \times y \times y \times (5y + 7)} \\ \\ = > \frac{3 \times y \times (5y - 7)}{1} \end{gathered}$

Hope it's helps you.

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