(3a-1)(3a-1)-6a+2 factorize the following polynomial
Answers
Answered by
1
(3a - 1) (3a -1)-6a + 2
=(3a - 1)^2-6a+2
=(3a) ^ 2+ 2*3a*1+ (1)^2 -6a + 2
=9a ^ 2 + 6a + 1- 6a + 2
=9a ^ 2 + 3
=3(3a ^ 2+ 1)
=(3a - 1)^2-6a+2
=(3a) ^ 2+ 2*3a*1+ (1)^2 -6a + 2
=9a ^ 2 + 6a + 1- 6a + 2
=9a ^ 2 + 3
=3(3a ^ 2+ 1)
Answered by
4
(3a-1) (3a-1) - 6a + 2
3a (3a-1) - 1 (3a-1) - 6a + 2
9a² - 3a - 3a + 1 - 6a + 2
9a² - 6a + 1 - 6a + 2
9a² - 12a + 3
9a² - 9a - 3a + 3
(9a² - 9a) - (3a + 3)
9a (a-1) - 3(a-1)
(a - 1) (9a - 3)
Hope it helps!!!!
3a (3a-1) - 1 (3a-1) - 6a + 2
9a² - 3a - 3a + 1 - 6a + 2
9a² - 6a + 1 - 6a + 2
9a² - 12a + 3
9a² - 9a - 3a + 3
(9a² - 9a) - (3a + 3)
9a (a-1) - 3(a-1)
(a - 1) (9a - 3)
Hope it helps!!!!
Similar questions