3a-1/5 = a/5 + 27/5 so find this in linear equation
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Heya friend,
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3a - 1/5 = a/5 + 27/5
=> 3a - 1/5 = a + 27/5
=> 5(3a - 1) = 5(a + 27)
=> 15a - 5 = 5a + 135
=> 15a - 5a = 135 + 5
=> 10a = 140
=> a = 140/10
=> a = 14
Thanks
With regards@
Tanisha
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3a - 1/5 = a/5 + 27/5
=> 3a - 1/5 = a + 27/5
=> 5(3a - 1) = 5(a + 27)
=> 15a - 5 = 5a + 135
=> 15a - 5a = 135 + 5
=> 10a = 140
=> a = 140/10
=> a = 14
Thanks
With regards@
Tanisha
Answered by
16
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