Math, asked by ashik2, 1 year ago

divide the numbers 45,53,61,65,70by5and note the remainders.what is the speciality of numbers leaving no remainder on dividing by 5

Answers

Answered by Ronak0020
0
Hi,
on dividing 45 by 5 remainder remains is 0
53 by 5 = 3 (remainder)
61 by 5 is 1
65 by5 is 0
70 by5 is 0

Observation- We observe that no. having 5 or 0 at their unit place does not have any remainder left when divided by5
and no. which are having no. more than 0 and less than 5 at unit place when divided left the same no. as remainder (unit place no).


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