Question

3a + 1 whole square plus b minus 1 whole square + 2 x minus 3 whole square is equal to zero to find 3A + b + 2c​

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Answer 1

Given :   (3a + 1)²  + (b - 1)²  + (2c - 3)²  = 0

To find :  Value of 3a + b + 2c

Solution:

(3a + 1)²  + (b - 1)²  + (2c - 3)²  = 0

As Sum of 3  Sqaures terms is zero

Hence each qaure term would be zero

=> 3a + 1  = 0

=> 3a = - 1

b - 1  = 0

=> b = 1

2c  - 3  = 0

=> 2c  = 3

Adding all three

3a + b  + 2c  =  -1  + 1 + 3

=> 3a + b + 2c  = 3

3a + b + 2c  = 3

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