Math, asked by rishabtiwari68456, 7 months ago

(3a^2-1) (-3a^2+5) in standard form​

Answers

Answered by bagkakali
1

Answer:

(3a^2-1)(-3a^2+5)

== -3a^4+3a^2+15a^2-5

= -3a^4+18a^2-5

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