Math, asked by mbittu221, 7 months ago

3a-2 /3+2a+3/2=a+7/6​

Answers

Answered by gautamkumar7289
0

Answer:

right answer of your questions

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Answered by tuktuki8
0

Answer:

Let us rearrange the equation (3a-2)/3 + (2a+3)/2 – a = 7/6

By taking LCM for 2 and 3 which is 6

((3a-2)2 + (2a+3)3 – 6a)/6 = 7/6

(6a – 4 + 6a + 9 – 6a)/6 = 7/6

(6a + 5)/6 = 7/6 6a + 5 = 7

6a = 7-5

6a = 2

a = 2/6 a = 1/3

Let us verify the given equation now,

(3a-2)/3 + (2a+3)/2 = a + 7/6

By substituting the value of ‘a’ we get

(3(1/3)-2)/3 + (2(1/3) + 3)/2 = 1/3 + 7/6

(1-2)/3 + (2/3 + 3)/2 = (2+7)/6

-1/3 + (11/3)/2 = 9/6

-1/3 + 11/6 = 3/2

(-2+11)/6 = 3/2

9/6 = 3/2

3/2 = 3/2

Hence, the given equation is verified.

Step-by-step explanation:

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