find the value of k (x-3)is a factor of p(x)=2x3-5x2+3x+k
Answers
Answered by
0
Answer:
x-3=0 then x=3 value of k=-52×3-5×2+3×3+k =06-10+9+k =05+k =0k =-5
Step-by-step explanation:
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Answered by
1
Answer:
let x-3=0
x= 3
put the value of x in p(x)
2x³-5x²+3x+k=0
2(3)³-5(3)²+3(3)+k=0
2×27-5×9+9+k=0
54-45-9+k=0
54-54+k=0
0+k=0
k=0
hope it will help you
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