Question

3a^2+a-2 factorise the following
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Answer 1

$\fcolorbox{pink}{yellow}{Answer:}$

$3 {a}^{2} + a - 2 = 3 {a}^{2} + 3a - 2a - 2 \\ = 3a(a + 1) - 2(a + 1) \\ = (a + 1)(3a - 2)$

factors of the given quadratic equation are,

(a+1) and (3a-2)

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Answer 2

Answer:

[ 3a - 2 ] [ a + 1 ]

Step-by-step explanation:

=> 3a ^2 + a - 2

=> 3a ^2 + 3a -2a - 2

=> [3a ^2 + 3a ] - [ 2a + 2 ]

=> 3a [ a + 1 ] - 2 [a + 1 ]

=> [ 3a - 2 ] [ a + 1 ]

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