Question

3a 2 x 2 + 8abx +4b 2 = 0 solve

Answer 1

3a²x²+8abx+4b²=0
or, $x= \frac{-8ab+- \sqrt{ (8ab)^{2}-4.3 a^{2}.4 b^{2} } }{2.3 a^{2} }$
or, $x= \frac{-8ab+- \sqrt{64 a^{2} b^{2}-48 a^{2} b^{2} } }{6 a^{2} }$
or, $x= \frac{-8ab+- \sqrt{16 a^{2} b^{2} } }{6 a^{2} }$
or, $x= \frac{-8ab+-4ab}{6 a^{2} }$
Either, [tex]x= \frac{-8ab+4ab}{6 a^{2} } [/tex]
or, $x= \frac{-4ab}{6 a^{2} }$
or, $x=- \frac{2b}{3a}$
Or, $x= \frac{-8ab-4ab}{6 a^{2} }$
or, $x= \frac{-12ab}{6 a^{2} }$
or, $x=- \frac{2b}{a}$
∴, $x= -\frac{2b}{3a}, - \frac{2b}{a}$ Ans.

Answer 2

Answer:

your answer is in the attachment

Step-by-step explanation:

hope it helps you