Question

3a 2 x 2 +8abx+4b 2 =0 solve it by quadratic formula

Answer 1

Answer:

$x=\frac{-2b}{3a}\: Or \:\frac{-2b}{a}$

Step-by-step explanation:

Compare 3a²x²+8abx+4b²=0 with Ax²+Bx+C=0 , we get

A=3a², B=8ab , C = 4b²

Discreminant (D)=B²-4AC

= (8ab)²-4×(3a²)(4b²)

= 64a²b²-48a²b²

= 16a²b²--(1)

/* By Quadratic Formula:

$x = \frac{-B±\sqrt{D}}{2A}$

$x = \frac{-8ab±\sqrt{16a^{2}b^{2}}}{2\times 3a^{2}}$

$=\frac{-8ab±4ab}{6a^{2}}$

$x=\frac{-8ab+4ab}{6a^{2}}\: Or \:\frac{-8ab-4ab}{6a^{2}}$

$x=\frac{-4ab}{6a^{2}}\: Or \:\frac{-12ab}{6a^{2}}$

$x=\frac{-2b}{3a}\: Or \:\frac{-2b}{a}$

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Answer 2

Answer:

Step-by-step explanation:

Compare 3a²x²+8abx+4b²=0 with Ax²+Bx+C=0 , we get

A=3a², B=8ab , C = 4b²

Discreminant (D)=B²-4AC

= (8ab)²-4×(3a²)(4b²)

= 64a²b²-48a²b²

= 16a²b²--(1)

/* By Quadratic Formula:

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