Question

(3a-2b+5c)^2 expand the following

Answer 1

Step-by-step explanation:

(3a-2b+5c)²

$(a - b + c) ^{2} = a {}^{2} + {b}^{2} + {c}^{2} + 2( - ab - bc + ac)$

9a²+4b²+25c²+2(3a×-2b-2b×5c+3a×5c)

9a²+4b²+25c²+2(-6ab-10bc+15ac)

9a²+4b²+25c²-12ab-20bc+30ac

Answer 2

$\huge{ \mathbb{ \color{aqua}{ศསຮཡཛཞ}}}$

${ \small{ \color{brown}{we \: have( \times + y + z {)}^{2} = { \times }^{2} + {y}^{2} + {z + }^{2} }}}$

${ \small{ \color{aqua}{2( \times y + yz + z \times )}}}$

${ \small{ \color{grey}{take \times = 3ay = - 26 \: and \: z = 5c}}}$

$\small{ \color{blue}{(3a - 26 + 5c {)}^{2} = (3a {)}^{2} + ( - 26 {)}^{2} + (5c {)}^{2} + }}$

$\small{ \color{black}{2(3a \times 2b + ( - 2b) \times 5c + 5c \times 3a)}}$

${ \small{ \color{lime}{ = 9 {a}^{2} + 4 {b}^{2} + 25 {c}^{2} - 12ab - 20bc + 30ac}}}$

$\small{ \color{pink}{(3a - 2b + 5c {) }^{2} = 9 {a}^{2} + 4 {b}^{2} + 25 {c}^{2} - }}$

${ \small{ \color{red}{12ab - 20bc + 30ac}}}$