If a+b+c=12, ab+bc+ca=37 and a^2+b^2+c^2=70 then find the value of a,b and c
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Answer:
74
Step-by-step explanation:
(a + b + c)^2 = a2 + b2 + c2 + 2( ab + bc + ca )
12 square = a2 + b2 + c2 + 74
144 - 74 = a^2 + b ^2 + c^2
74..
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