Question

3a^2bc+9ab^c+21abc^2
Factorise the following

Answer 1

Answer:

$a + 3b + 7c= 0$

Step-by-step explanation:

$3a {}^{2} bc + 9ab {}^{2} c + 21ab {c}^{2} = 0$

$3(a {}^{2} bc + 3ab {}^{2} c + 7abc {}^{2} ) = 0$

$a {}^{2} bc + 3ab {}^{2} c + 7abc {}^{2} = 0$

$a(abc + 3 {b}^{2} c + 7b {c}^{2} ) = 0$

and so on...then finally

$bc(a + 3b + 7c) = 0$

therefore,

$a + 3b + 7c= 0$