Question

3a=46=6c find √a²+b²+c²​

Answer 1

Answer:

Step-by-step explanation:

√(a² + b² + c²) = 87  if 3a = 4b = 6c  & a + b + c = 27√29

Step-by-step explanation:

Missing information :

3a = 4b = 6c

Let say 3a = 4b = 6c  = 12k

=> a = 4k  

b = 3k  

c = 2k

a + b + c = 27√29

4k + 3k + 2k = 27√29

=> 9k = 27√29

=> k = 3√29

a = 4k = 12√29

b = 3k = 9√29

c = 2k = 6√29

√(a² + b² + c²)

= √ ( (12√29)² + (9√29)² + (6√29)²)

= √(29)( 144 + 81 + 36)

= √(29(261)

= √29 * 29 * 9

= 29 * 3

= 87

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