Question

What volume of 0.100 N HNO3 is required to neutralize 50.0 mL of a 0.150 N solution of Ba(OH)2?
Select one:
O a. 75.0 mL
O b. 125 ml
O c. 50.0 mL
O d. 100. mL​

Answer 1

Answer:

The answer is a option B

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Answer 2

Concept

neutralization or neutralisation could be a chemical change during which acid and a base react quantitatively with one another.

Given

We are provided that we've to neutralize $50.0mL$ of a $0.150N$ solution of $Ba(OH)_2$.

Find

We have to seek out the specified volume of $0.100N \text{ } HNO_3$.

Solution

Here, we are going to use the formula $N_\text{acid}\times V_\text{acid}=N_\text{base}\times V_\text{base}$                     ......(1)

We are given $N_\text{acid}=0.1N,N_\text{base}=0.150N,V_\text{base}=50mL.$

Substitute of these values in equation (1), we get

$\begin{aligned}0.1\times V_\text{acid}&=0.150\times 50\\ V_\text{acid}&=\frac{0.150}\times {0.1}\\ V_\text{acid}&=75mL\end$

Hence, $75mL$ volume is required to neutralize the $Ba(OH)_2.$

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