Question

3a-[4a-{2a+(a-2b-3c) +c}]​

Answer 1

3a–[4a–{2a+(a–2b–3c)+c}]

=3a–[4a–{2a+a–2b–3c+c}]

=3a–[4a–3a+2b+2c]

=3a–a–2b–2c

=2a–2b–2c

=2(a–b–c)

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