Question

(3a + 4b)³ expand using identity (x+y)³=x³+y³+3xy(x+y)

Answer 1

(3a)^3+(4b)^3+3(3a) (4b) (3a+4b)

=27a^3+64b^3+24ab(3a+4b)

=27a^3+64b^3+72a^2b+96ab^2