(3a-4b) ki cube by using indetities
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Answered by
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hiiii dear here is ur answer
(3a-4b)
a³_b³_3ab(a+b)
→(3a)³-(4b)³_3(3a)(4b)[3a-4b]
→21a³_64b³-9a-12b(3a-4b)
→21a³-64b³-27a²+36ab-36ab+48b²
→21a³-64b³_27a²+48b²
→
Answered by
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(3a-4b)³
= we know that, (a-b)³ = a³-b³-3ab(a-b)
= 27a³- 64b³-3*3a*4b(3a-4b)
= 27a³ - 64b³ - 36ab(3a - 4b)
= 27a³ - 64b³ - 108a²b + 144ab²
Hope that answered your question.
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