Question

(3a+5b)² -4c



plz solve this ​

Answer 1

Answer:

Hello Dear User__________

Here is Your Answer...!!

____________________

Step-by-step explanation:

$Given \ (3a+5b)^{2}-4c\\\\We \ have \ to \ solve \ it\\\\using \ identity \ (a+b)^{2}=a^{2}+ b^{2}+2ab \ here\\ \\(3a+5b)^{2}-4c=9a^{2}+25b^{2}+30ab-4c\\ \\(3a+5b)^{2}-4c=9a^{2}+25b^{2}-4c+30ab$

Hope it is clear to you.

Answer 2

Heya..

your answer is....

given:

(3a+5b)² -4c

this is in the form of (a+b)²

so,

(3a+5b)² =9a²+30ab+25b²

$= > 9a {}^{2} + 30ab + 25b {}^{2} - 4c$

hope it helps you