Question

3a+9b+c=42 a,b,c are all prime numbers. What is the value of a+b+c?​

Answer 1

Answer:

3a + 9b +c = 42

3x + 9x + x = 42

13x = 42

x = 42/13

x = 3

3a = 3*3 = 9

9b = 9*3 = 27

c = 3

Answer 2

If 3a + 9b + c = 42

==> a,b,c are prime numbers

Find

==> value of a+b+c

Let

==> a = 2 , b = 3 , c = 5 ( all are prime numbers )

Now

==> 3a + 9b + c = 42

==> 3(a) + 9(b) + c = 42

==> 3(2) + 9(3) + 5 = 42

==> 6 + 27 + 5 = 42

value of a + b + c =

a = 6

b = 27

c = 5

value of a + b + c = 6 + 27 + 5 = 38