Question

Calculate the rate of work done on an object of mass 1kg lifted to a height of lm by
taking a time of 2 seconds. Take g=10 m/s?​

Answer 1

Step-by-step explanation:

Work done by gravity = -mgh = -1×1×2 = -2Joule

In order to lift S = 1m u = 0

-1= 1/2[-10] t²

t = 1/√5 sec.

For 1/√5 sec > 2 joule work

1= 2√5 joule

2= 4√5 done

Rate = 2√5 Joule/ sec